WebIf p th term of an A.P. is q and its q th term is p. Show that its r th term is (p+q− r). Hard View solution > If the pth term of an A.P. be q and qth term be p, prove that the (p+q)th term is zero. Easy View solution > View more Get the Free Answr app Click a picture with our app and get instant verified solutions WebIn an A.P, if the p th term is 1/q and q th term is 1/p, prove that the sum of first pq terms is 1/2 (pq + 1), where p ≠ q. Solution: It is known that general term of an A.P is a n = a + (n - 1) d p th term = a n = a + (n - 1) d = 1/q .... (1) q th term = a n = a + (n - 1) d = 1/p .... (2) Subtracting (2) from (1) , we obtain
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WebIf the pth, qth and rth terms of an A.P. be a, b and c respectively, then prove that a(q−r)+b(r−p)+c(p−q)=0. Medium Solution Verified by Toppr Let A be the first term and D the common difference of A.P. T p=a=A+(p−1)D=(A−D)+pD (1) T q=b=A+(q−1)D=(A−D)+qD ..(2) T r=c=A+(r−1)D=(A−D)+rD ..(3) WebIf the pth, qth, rth terms of an AP be x, y, z respectively, show that x(q – r) + y(r – p) + z(p – q). Q13. If the pth term of an AP is 1/q and the qth term is 1/p, show that the sum of pq terms is ½(pq + 1). LONG ANSWER TYPE QUESTIONS Q14. In an AP of 50 terms, the sum of first 10 terms is 210 and sum of its last 15 terms is 2565.
WebApr 21, 2024 · If pth, qth and rth terms of an A.P are a, b and c respectively, then:- Q10. If a, b, c be in A.P, then ( a − c) 2 ( b 2 − a c) is More Sequences and Series Questions Q1. If n harmonic means are inserted between 1 and r, then 1 s t m e a n n t h m e a n = Q2. The arithmetic mean of 1, 2, 3, 4, …. n numbers will be : Q3. WebIf in an A.P., the pth term is q and (p + q)th term is zero, then the qth term is (a) - p (b) p (c) p + q (d) p - q Q. If in an A.P., the pth term is q and (p + q)th term is zero, then the qth term is Q. The pth term of an A.P. is a and qth term is b. Prove that sum of its (p+q) terms is p+q 2 [a+b+ a−b p−q]. Q.
WebAug 20, 2024 · In an A.P. the pth term is q and the (p + q)th term is 0. Then the qth term is (A) – p (B) p (C) p + q (D) p – q sequences and series class-11 1 Answer 0 votes answered Aug 20, 2024 by AbhishekAnand (88.0k points) selected Aug 20, 2024 by Vikash Kumar Best answer (B) is the correct answer WebOct 29, 2024 · pth term of an AP = q qth term = p Prove: nth term of A.P. is (p+q-n). Proof: We know that, nth term of an AP (an) = a + (n - 1)d Hence, a + (p - 1)d = q a + pd - d = q a = q - pd + d -- equation (1) Similarly, a + (q - 1)d = p Substitute the value of a from equation (1). q - pd + d + qd - d = p qd - pd = p - q - d(p - q) = p - q - d = 1
WebMar 16, 2024 · If the pth term of an AP is q and the qth term is p, prove that its nth term is (p + q – n). cbse class-10 1 Answer 0 votes answered Mar 16, 2024 by santoshjha (143k points) selected Mar 27, 2024 by Vikash Kumar Best answer The correct answer is ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test …
WebMar 30, 2024 · We know that an = a + (n 1)d Where an is nth term of AP, n is the number of terms, a be the first term & d be the common difference of the A.P. It is given that pth term is 1/ i.e. ap = 1/q a + (p 1)d = 1/q Also, qth term of A.P = 1/p i.e. aq = 1/p i.e. a + (q 1)d = 1/p Now subtracting (1) from (2) i.e. (1) (2) [a + (p 1)d] [a + (q 1)d] = 1/ 1 ... orals leaving cert 2022WebSep 29, 2024 · Click here 👆 to get an answer to your question ️ the pth term of an AP is q and qth term is p. find its (p+q)th term. hardeechoudhary ... Secondary School answered • expert verified The pth term of an AP is q and qth term is p. find its (p+q)th term. See answers how can i mark beacaise only one solution had came yet bacause* ... orals prep rfpWebJul 20, 2024 · pth term is Step-by-step explanation: Since we have given that (p+q) th term of an AP = m (p-q) th term of an AP = n. So, it becomes, so, it becomes, So, first term would be . So, the value of pth term would be . Hence, pth term is # learn more: If tn denotes the nth term of the series 2+3+6+11+18+.....,then find t50. brainly.in/question/3103109 orals rfpWebMar 29, 2024 · Show that (q r) a+ (r p)b+ (p q) c = 0 Here we have small a in the equation, so we use capital A for first term We know that, An = A + (n 1) D where An is the nth term of A.P. n is the number of terms A is the first term, D is the common difference It is given that pth term of an AP is a i.e. Ap = a Putting n = p A + (p 1) D = a a = A + (p 1)D … orals for msWebJan 14, 2024 · Best answer Solution: Given pth term = 1/q That is ap = a + (p - 1)d = 1/q aq + (pq - q)d = 1 --- (1) Similarly, we get ap + (pq - p)d = 1 --- (2) From (1) and (2), we get aq + (pq - q)d = ap + (pq - p)d aq - ap = d [pq - p - pq + q] a (q - p) = d (q - p) Therefore, a = d Equation (1) becomes, dq + pqd - dq = 1 d = 1/pq Hence a = 1/pq ip power camerasWebApr 7, 2024 · a + ( p − 1) ⋅ ( − 1) = q ⇒ a − p + 1 = q ∴ a = p + q − 1. Hence, the first term of this arithmetic progression is (p + q – 1). Thus, in order to get the nth term of the AP, we simply need to put the values of the first term and common difference of … ip power coilWebThe p th, q th and r th terms of an A.P are a,b,c respectively. Show that (q−r)a+(r−p)b+(p−q)c=0. Medium Solution Verified by Toppr Let a= First term of the AP and d= Common difference of the AP Now, a=A+(p−1)d....(1) b=A+(q−1)d....(2) c=A+(r−1)d....(3) Subtracting (2) from (1), (3) from (2) and (1) from (3), we get a−b=(p−q)d....(4) oralsed